Page 1 of 1

X in good times pay

Posted: Thu May 24, 2012 7:19 am
by nova369


Boucharda asked in chat, how does one get 2  7x pay when there is only one per hand..... Just to let you know I just got 2  7x pay in one hand...had 2 7x and 1  1x.....didnt get anything but I had 2 7x in one hand.

Re: X in good times pay

Posted: Thu May 24, 2012 8:47 am
by Webman
Not sure I'm following.... which game type were you playing? DDB, JB, etc.


Re: X in good times pay

Posted: Thu May 24, 2012 2:57 pm
by edog743
I was playing TDB yesterday in contest got two x7 a few times. in grid of multipliers there is only one x7  If you look at the leaders hands he got two hands in one deal x7 how is that possible?

Re: X in good times pay

Posted: Thu May 24, 2012 3:21 pm
by Webman
Each line has the multiplier selected independently. Sometimes they select the same position.


Re: X in good times pay

Posted: Thu May 24, 2012 3:27 pm
by edog743
Ok  with that logic there should only be one of each number on the grid. but there is not. Interesting

Re: X in good times pay

Posted: Thu May 24, 2012 3:39 pm
by Webman
Not really... I think there are more 1x's for instance because the odds of 1x are much higher than a 7x. I don't know if the odds of each spot are the same but I can find out. I know that was asked in the past but I don't recall the answer.


Re: X in good times pay

Posted: Thu May 24, 2012 9:28 pm
by New2vp
Post unable to migrate

Re: X in good times pay

Posted: Thu May 24, 2012 11:04 pm
by Webman
I checked and the word is that the odds of each multiplier space are equal, for all 3 lines.