Best guess

[pokeherguy]

I did go stupid for a second on the payback percentage it is of corse 98.98%.

[New2vp]

Hey new, is that value greater than a google? I first heard that word in Geometry and it stuck in my head until they decided to use it for a search engine.There's a "ton" of vigintillions in a googol.  I know I shouldn't be so colloquial when discussing such a serious subject.  Actually there are 10 undecillion (see the last post) vigintillions in a googol.  If you're keeping track of the exponents in scientific notation, that makes the number of zeros in a googol equal to 100.  As the legend goes, the googol was named by an elementary school relative of some published mathematician in the '30s or '40s.I agree with those who are choosing to skip the readings of the these posts.  There's not a lot of use for most of these numbers.Quoting an old Quaker State commercial, they were probably invented by guys who had more degrees than they had dates.

[New2vp]

I did go stupid for a second on the payback percentage it is of corse 98.98%.Oh, no!  Now, I need to change my numbers.  Oh well, I'll go ahead and let 'em ride.

[pokeherguy]

Royal Flush=3
Aces w/kicker=2
Aces & 2,3,4's w/kicker=24
2,3,4's=33
Straight Flush=5
Misc. Quads=237
Royal Butt Kicking=1
 
When I say near perfect play I'm not completely sure at times I do the right thing always. I had several times when I was dealt a full house that included 3-Aces and I always went for the Aces, never converted one but a few times I did get another full house. I also toss away dealt full houses that include 3-2,3,4's. Whatever happened to that Rolanddude I need a new strategy?

[New2vp]

1 in a Vigintillion?
 
"So you're telling me there's a chance!"Didn't like the movie much, but one of my all time favorite lines.

[cddenver]

I know you were making a joke, but in continuing this nonsense you are off by 36 zeros on undecillion ["un" + "dec" = (1 + 10) x 3 + 3 = 36].  The word you wanted for 66 zeros is unvigintillion ["un" + "vigin" = (1 + 20) x 3 + 3 = 66].

 

  That's what I get looking for that info in the "Answers" section of Yahoo.  The "Best Answer" to a question for a "-llion" list shows "undecillion" twice, with 36 zeros and 66 zeros.  I just went back and checked some of the other responses:
 
66 - 120 zeros, undecillion - vigintillion
303 zeros, centillion
 
That response really cleared things up for me (not).  I assume that refers to cycling through undecillion to vigintillion in some fashion.  I also found one that agreed with you, 66 zeros = unvigintillion.  Those folks went off-topic quickly and I lost interest after about 50 posts arguing over whether it's possible to add one to infinity.
 

A bizillion is what a speech-challenged geographer calls people from the largest South American country.

 
Groan.  

[New2vp]

Royal Flush=3
Aces w/kicker=2
Aces & 2,3,4's w/kicker=24
2,3,4's=33
Straight Flush=5
Misc. Quads=237
Royal Butt Kicking=1
 
When I say near perfect play I'm not completely sure at times I do the right thing always. I had several times when I was dealt a full house that included 3-Aces and I always went for the Aces, never converted one but a few times I did get another full house. I also toss away dealt full houses that include 3-2,3,4's. Whatever happened to that Rolanddude I need a new strategy?I've done a lot of joking around on this subject since you introduced it and suggested that there was not much use for some of the numbers.  However, your results are no joking matter.  It's hard to imagine worse results with a reasonable strategy and a fair machine.  And most strategy has relatively little effect on the number of quads to expect, so we really cannot credibly blame the poor number of quads on the strategy used.  Pretty much keeping pairs and trips will generally yield a reasonable number of quads.  In my mind, that leaves only a couple possibilities.  Either your record-keeping is faulty (which I presume is not the case) or the machines are fixed.  There may be another reason, but it doesn't come to mind easily.If you had given the results by line without mentioning the number of hands played, I would have pegged the number of hands at 70,849....way lower than 150,000.  And I would have told you that you got a great break on the royals and that the number of miscellaneous quads still was too high to be believed.The number of royals was right on target for 150,000 hands; 3 is the most likely number.  The number of miscellaneous quads is a bit on the low side, but not unreasonably so (about 2-1 odds of finishing this low or lower).  However, the other 4 categories are more than suspiciously low.  It wouldn't be that unusual to have one category that bad...but all four of these makes me believe that there are some irregularities going on.  My conjecture would be that whoever is responsible is trying to avert suspicion by not affecting the number of royals or the number of miscellaneous quads.  But the other lines are way too low.With perfect strategy and a fair machine you would see results this low or lower with the following odds on a line by line basis:Aces w/kicker=2                        193 to 1 against
Aces & 2,3,4's w/kicker=24      7870 to 1 against
2,3,4's=33                               3335 to 1 against
Straight Flush=5                        990 to 1 againstThere is way too much bad luck going on here to be simply chance.  I would find another place to play or take up another hobby.I would be happy to entertain other explanations, but this doesn't look to be on the up and up.

[cddenver]

Royal Flush=3
Aces w/kicker=2
Aces & 2,3,4's w/kicker=24
2,3,4's=33
Straight Flush=5
Misc. Quads=237
Royal Butt Kicking=1
 
If you look at the ranges posted by New2vp and Eduardo for all your Aces and all your 2's-4's you'll see you fell into the very low end over those 150K hands, well below the long-term average amounts.   It's very unlikely that all those quad types would be so low over the same play.  The Miscellaneous quads are somewhat low but not overly so.  If they were proportionally as low as the other categories I'd say that whatever calculations you used to determine the number of hands played (150K) aren't right, and the total number of hands played was substantially less. 
 
But, there are those Miscellaneous quads which are least in the ballpark for 150K hands which would shoot down the thinking that your hands played was much less than 150K.  
  

[New2vp]

 

  That's what I get looking for that info in the "Answers" section of Yahoo.  The "Best Answer" to a question for a "-llion" list shows "undecillion" twice, with 36 zeros and 66 zeros.  I just went back and checked some of the other responses:
 
66 - 120 zeros, undecillion - vigintillion 303 zeros, centillion
 

That response really cleared things up for me (not).  I assume that refers to cycling through undecillion to vigintillion in some fashion.  I also found one that agreed with you, 66 zeros = unvigintillion.  Those folks went off-topic quickly and I lost interest after about 50 posts arguing over whether it's possible to add one to infinity. There's a method to the "madness" that is not too hard to understand, but I admit it takes a bit of patience.  I've never seen this written anywhere like this, but here is what I do.1.  Take the number of zeros (z) and subtract 3 (z-3).  2.  Divide this difference by 3.  Look at the quotient (x) and save the remainder (y) of 0, 1, or 2 for later.
3.  Find the Latin prefix corresponding to x and add -illion to the word.  I never took Latin, so I'm not certain of some of the bigger numbers but we generally won't get too high.  Also, it seems that the direct translation for what we would call "twenty-one" is "one and twenty," so some of the more complicated prefixes seem like they are backwards.4.  If the remainder (y) was 0, we're done; if it was 1, we say 10 somethingillion; if it was 2, we say 100 somethingillion.So, with your examples above, we can find our answers fairly easily:66 zeros:(66 - 3) / 3 = 21 or one and twenty corresponding to "un-" + "vigint-" + "illion" or 1 vigintillion.120 zeros:(120 - 3) / 3 = 39 or nine and thirty corresponding to "novem-" + "trigint-" + "illion" or 1 novemtrigintillion.  I have never seen this name before and figured it would not be on the Web but when I googled it, there were 1120 hits.303 zeros:(303 - 3) / 3 =100 which correctly makes "cent-" + "illion" or 1 centillion.A googol does not fit under this system but has 100 zeros, so the name that does fit can be found by the same method.  The name of the popular search engine is a misspelling of the mathematical term.(100 - 3) / 3 = 32 remainder 1 which would be two and thirty corresponding to "duo-" + "trigint-" + "illion."  The remainder of one means we have an extra zero, so we need to multiply by 10:1 googol = 10 duotrigintillionMost of these terms are never expressed in this fashion because serious uses of them generally involve the symbols and exponents of scientific notation using a base of 10 raised to some power.Sorry, still no explanations for a bizillion, a jillion, a zillion, or even umpteen million.We now return to your regularly scheduled programming.

[cddenver]

Sorry, still no explanations for a bizillion, a jillion, a zillion, or even umpteen million.
 
Thank you for the, as always, excellent information.
 
Earlier tonight I did a google for "bizillion" and came up with a bizillion hits.  I looked at the first few pages, and they were all general references to large numbers like we use here.  No formal specifications.