Interesting trip to AC

[Player422738]

Long story short...

I drove to Harrahs, on arrival, I saw someone got really lucky...




I played a while and my luck arrived too.

[onemoretry]

Not $120000+, but pretty darned good!

[New2vp]

The first picture reminds me of a beloved poster from yesteryear, faygo. Hitting the progressive 5 aces on all 3 lines was his favorite game … and dream. His discussion of the game doesn't occur until the 2nd page of the thread below.

https://www.videopoker.com/forum/viewto ... f=2&t=3682

[Tedlark]

Thanks for blowing the dust off a quality thread New and RIP faygo.

[Come Back Kid]

Wow, what a hit for that lucky guy! Very nice hit for you too...Wtg!

[Tedlark]

Oops! CONGRATS to you too hophoofer.

I apologize for not saying so earlier.

[Player422738]

Thank you all guys!

For that 5 aces thing...the “easiest” way to win is get lucky to be dealt with 5 aces. No strategy is needed. Chance is 1 in 2,869,685. Hitting the jackpot by drawing the last ace on all 3 hands when 4 aces are dealt is much harder. The chance is 1 in 1,295,364,096 (2,869,685 / 5 / 49 * (48^3)), if I am not mistaken...

[Carcounter]

I took at potshot at this game when the jackpot was over 100k several years ago. was dealt 4 aces (3 aces and the Joker) so close! Connected on one line for $1,000.

[New2vp]

Thank you all guys!

For that 5 aces thing...the “easiest” way to win is get lucky to be dealt with 5 aces. No strategy is needed. Chance is 1 in 2,869,685. Hitting the jackpot by drawing the last ace on all 3 hands when 4 aces are dealt is much harder. The chance is 1 in 1,295,364,096 (2,869,685 / 5 / 49 * (48^3)), if I am not mistaken...

Hey hh, Not that anyone is going to make any changes based on this (nor will most even try and understand), but the chances are slightly worse at 1 in 1,322,350,848. If you change the number 49 in your calculation to 48, I think you will get the same answer. There are 48 cards from 2 thru king (non ace/joker), not 49.

For those who don't follow what you did, if you let the joker stand as the 5th ace, there are 240 ways to get 4 aces on the deal; i.e., 5 different ways to get four aces by leaving out one of the five ace/joker cards multiplied by the 48 ways to get the single card that is from two through king. 5 x 48 = 240. So the probability for this type of deal is 240 / 2,869,685. Then, as you correctly note, you need to draw the last ace/joker from the 48 remaining cards and you need to do that on all three hands, so that probability of the necessary draw is as you indicated (1/48)*(1/48)*(1/48) or 1/(48^3) = 1 / 110,592.

Multiplying those together gets you 240 / 317,364,203,520. Dividing both the numerator and denominator by 240 leaves you with 1 / 1,322,350,848.

So, Carcounter's draw was one of the 110,591 "non-jackpot" draws! 103,823 of the 110,592 draws would have yielded zero (of 3) hits of five aces. He still did pretty good by hitting even one of the hands!!

And we will not try and deal with how you can get 3 hands of 5 aces by drawing 2, 3, 4, or even 5 cards after the deal using max EV (or any other) strategy !!

[New2vp]

Thanks for blowing the dust off a quality thread New and RIP faygo.

You're welcome, Ted. There were some interesting posts and posters in that era. Even the drama back then was interesting. Does this reminiscing mean we're getting old??